Recent comments in /f/headphones

kemnitz t1_j5w2c21 wrote

Reply to HD 650 ruined me by GLikesSteak

I find Philips Fidelio 2XHR are a perfect compliment to HD650's. They are the headphone for that "grand" music the 650's can't deliver on. Go buy some now!

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Plexaporta t1_j5w0kyh wrote

Reply to comment by xGuacamolly in HD600 = absolute Endgame by xGuacamolly

I just got it last month for €200.

Great sounding dac, use it as a headphone amp for now.

Might integrate it in my 2 channel set as a standalone dac.

Currently using a highly modified Behringer Ultracurve Pro DEQ 24/96 as roomcorrection/dac.

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TaliskerBay22 t1_j5w0hju wrote

Reply to comment by No-Tune-9435 in what information an impulse response graph provides about headphones? by MEGA_AEOIU792

Look here is an example, the time domain lasts for a ms and the Fourier response extends from 0 to some tens of KHz. Plug it in Matlab and tweak it as you like

% Define time-domain signal
dt = 0.000001; % time step (s)
t = 0:dt:0.001; % time vector (s)
x = cos(50000.*t-0.0004).*exp(-(t-0.0003).^2/0.00006^2); % time-domain signal
% Perform FFT
X = fft(x); % FFT of time-domain signal
f = (0:length(X)-1)/(dt*length(X)); % frequency vector (Hz)
% Plot results
figure;
subplot(2,1,1);
plot(t,x);
xlabel('Time (s)');
ylabel('Amplitude');
title('Time-domain signal');
subplot(2,1,2);
Amplitude=abs(X);
semilogy(f(1:length(X)/20),Amplitude(1:length(X)/20));
xlabel('Frequency (Hz)');
ylabel('Amplitude');
title('Frequency-domain signal (FFT)');

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blutfink t1_j5w0fke wrote

Reply to comment by No-Tune-9435 in what information an impulse response graph provides about headphones? by MEGA_AEOIU792

In the extreme case? Infinitesimally short time. The FT of a Dirac pulse is a flat, constant response from 0 Hz to infinity Hz (or, in the case of DFT, Nyquist frequency).

As I said, the FT of a Gaussian is a Gaussian. Really sharp in the time domain means really wide in the frequency domain. If you do not understand why that is, your intuition about FTs will be flawed.

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blutfink t1_j5vz4wj wrote

Reply to comment by No-Tune-9435 in what information an impulse response graph provides about headphones? by MEGA_AEOIU792

Proper decaying/windowing is performed via element-wise multiplication with a window function. All we want is that the signal is smoothly approaching zero at the edges. Since this is approximately the case for typical impulse responses of audio systems, it won’t change the result that much if you don’t window it at all.

To help your intuition, convince yourself that the FT of a centered Gaussian bell curve is itself a Gaussian bell curve. Note that the “low frequencies” in this graph are near the center.

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blutfink t1_j5vvd3w wrote

Reply to comment by No-Tune-9435 in what information an impulse response graph provides about headphones? by MEGA_AEOIU792

Of course. As in professionally, for decades. Note that for that to work, you need the full, complex-valued FR of a system. The amplitude response does not contain phase information.

That’s why people add the impulse response as supporting information: A plot of the complex-valued response (either 3D or as two real-valued graphs) is not intuitive for humans.

Here is a quick explanation of how the responses are calculated in REW.

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